StudentsParentsTeachersHelp ZoneAllofrançais
Help Zone
StudentsParentsTeachersHelp ZoneAllofrançais
Help Zone
Create an account
Home
Ask a question
Subjects
Mathematics
French
Coming Soon
Chemistry
Science and Technology
History
Physics
Geography
English Language Arts
Indigenous content
Coming Soon
Financial Education
Contemporary World
Grades
Grade 1
Grade 2
Grade 3
Grade 4
Grade 5
Grade 6
Secondary 1
Secondary 2
Secondary 3
Secondary 4
Secondary 5
Explore
Concept sheets
Exercises
Games
Videos
Crash Courses
Exam prep and study tips
Mathematics
French
Coming Soon
Chemistry
Science and Technology
History
Physics
Geography
English Language Arts
Indigenous content
Coming Soon
Financial Education
Contemporary World
Grade 1
Grade 2
Grade 3
Grade 4
Grade 5
Grade 6
Secondary 1
Secondary 2
Secondary 3
Secondary 4
Secondary 5
Concept sheets
Exercises
Games
Videos
Crash Courses
Exam prep and study tips

The Help Zone is under renovation.

See if your question has already been asked!

Physics
Secondary 5 • October 6, 2023
20231005_201935.jpgI'm having trouble solving this question. How would I do it?

Answer (1)

Student Answer
October 6, 2023
You can use the formula:
P=I^2R
Example
P = ?
P= I^2*R
R = 200 ohms
I = 6A
P= 36 * 200
= 7200w