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Chemistry
Secondaire 5 • February 1, 2024
Hello would anyone be able to explain me this type of chemistry question. I always seem to get these types of questions wrong and I just don’t understand why I’m not getting them. 678A7612-2CC7-432B-B90C-C47D4E77B13A.jpeg

Explanation (1)

Student Explanation
February 1, 2024
Hi SupraZinc, Thanks for your question! The ideal gas law is PV = nRT. Therefore, to determine P, you get P = (nRT)/V. Since R is constant, you can get rid of it for the exercice (since you don't need a true value of P, only a size comparison). Therefore, P = (nT)/V. The variables you wrote on the right of your picture are a great start! You can replace the variables in the ideal gas law with 1 if they remain unchanged and by 3 if they are trippled. So, initially, we have: P = (nT)/V = (1*1)/1 = 1 After the changes: P = (3*3)/3 = 3 So the pressure is tripled! You can always use this method for this kind of problem. Don't hesitate to reach out again if needed:) Kylan