Heat Calculations

Concept sheet | Science and Technology

Heat

When two substances of different temperatures are in contact, some of the thermal energy of the hotter substance is transferred to the colder substance, until the two substances reach the same temperature. Both substances then undergo a temperature change. The hot substance experiences a decrease in temperature because it releases thermal energy. The cold substance experiences an increase in temperature because it absorbs thermal energy. This phenomenon is called heat.

Definition

Heat is the transfer of thermal energy between two systems at different temperatures.

Heat flows from a hot substance to a cold substance.

Heat

The amount of heat absorbed or released by a substance depends on the mass of the substance, the specific heat capacity of the substance and the temperature change. Heat is calculated using the following formula.

Formula

|Q=mc\Delta T|

where

|Q\!:| heat in joules |(\text{J})|
|m\!:| mass in grams |(\text{g})|
|c\!:| specific heat capacity in joules per gram and degrees Celsius |(\text{J/g}{\cdot^\circ\!\text{C}})|
|\Delta T\!:| temperature change in degrees Celsius |(^\circ\text{C})|

Important!

The amount of heat |(Q)| is positive or negative depending on whether the substance absorbs or releases thermal energy.

  • When |Q| is positive, the substance absorbs thermal energy and its temperature increases.

  • When |Q| is negative, the substance releases thermal energy and its temperature decreases.

Specific Heat Capacity

Temperature Change

The temperature change of a substance |(\Delta T)| is the difference between the final temperature |(T_{\text{f}})| and the initial temperature |(T_{\text{i}}).| 

Formula

|\Delta T=T_{\text{f}}-T_{\text{i}}|

where

|\Delta T\!:| temperature change in degrees Celsius |(^\circ\text{C})|
|T_{\text{f}}\!:| final temperature in degrees Celsius |(^\circ\text{C})|
|T_{\text{i}}\!:| initial temperature in degrees Celsius |(^\circ\text{C})|

Calculation Examples |(Q=mc\Delta T)|

Example

How much heat is absorbed by a |0.475\ \text{kg}| iron cube when its temperature changes from |10^\circ\text{C}| to |22^\circ\text{C}|?

The specific heat capacity of iron is |0.45\ \text{J/g}{\cdot^\circ\!\text{C}}.|

See solution

Example

What mass of water releases |1100\ \text{J}| of thermal energy if its temperature decreases from |39.0^\circ\text{C}| to |20.5^\circ\text{C}|?

The specific heat capacity of water is |4.19\ \text{J/g}{\cdot^\circ\!\text{C}}.|

See solution

Example

In a lab, |260\ \text{J}| of heat is transferred to a |25\ \text{g}| block of unknown metal. The temperature rises from |24^\circ\text{C}| to |104^\circ\text{C}.|

Determine the specific heat capacity of the metal in order to identify it.

Specific Heat Capacity of Some Metals

Metal

Aluminum

Silver

Copper

Iron

Mercury

Lead

|\bf c|
|\bf (\text{J/g}{\cdot^\circ\!\text{C}})|

|0.90|

|0.24|

|0.39|

|0.45|

|0.14|

|0.13|

Source: Couture et al., (2011)[1]

See solution

Example

One litre |(1\ \text{L})| of antifreeze at |5.4^\circ\text{C}| absorbs |10\ 500\ \text{J}| of thermal energy. 
a) What is the temperature change of antifreeze?
b) What is the final temperature of antifreeze? 

The density |(\rho)| of antifreeze is |1.135\ \text{g/mL}.|

The specific heat capacity of antifreeze is |2.20\ \text{J/g}{\cdot^\circ\!\text{C}}.|

See solution

Example

In a lab, a |78\ \text{g}| aluminum ball with an initial temperature of |280^\circ\text{C}| is placed in |350\ \text{mL}| of water. After a few minutes, the water temperature reaches and stays at |28^\circ\text{C}.| Determine the initial temperature of the water.

The specific heat capacity of aluminum is |0.90\ \text{J/g}{\cdot^\circ\!\text{C}}| and of water is  |4.19\ \text{J/g}{\cdot^\circ\!\text{C}}.|

The density of water is |1.00\ \text{g/mL}.|

A 78-gram aluminum ball is immersed in an insulating glass filled with 350 millilitres of water. At the end of the thermal energy transfer, the temperature of the water is 28 degrees Celsius.

The transfer of thermal energy between an aluminum ball and water

See solution

Exercise

Exercise

Heat (Q = mc deltaT)

Science and Technology Secondary4

References