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Physique
Secondaire 5 • 8 août 2021
16284420673898411255115850210590.jpgHi I have trouble with this question. I think my notes don't give me enough informations.

This is the explanation I have
16284421196183681184456464605495.jpgBut how do I get theses values

Thank you

Explications (3)

Explication d’élève
9 août 2021
Ramzi,
coquilles à corriger:
ici \[G\cdot m=\frac{g_1}{r_1^2}\]
ici \[ g_2=\frac{\frac{g_1}{r_1^2}}{r_2^2}=\frac{g_1}{r_1^2\times r_2^2} \]
et ici \[ g_2=\frac{9.8}{(1)^2\times (4)^2}=\frac{9.8}{(4)^2} \]
Explication d’Alloprof
8 août 2021
Hi !
To get the same answer, you need a specefic formula that you can find by following this link :

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The link is in french, but you just need to look at the formula :
g=Gmr2 g=\frac{G\cdot m}{r^2}
In this case, the only thing you need to know is that \(r\) is the distance between the core of the planet and the altitude. Knowing that we're comparing to point for the same planet, \(G\) and \(m\) are the same. Now you can calculate the \(g\) for each situation. The first one is at the surface :
g1=Gmr12 g_1=\frac{G\cdot m}{r_1^2}
The second situation will be like this :
g2=Gmr22 g_2=\frac{G\cdot m}{r_2^2}
If you try to put the first formula in the second one (replace \(G\cdot m\)), you will get this :
Gm=g1r12 G\cdot m=\frac{g_1}{r_1^2}
g2=g1r12r22=g1r12×r22 g_2=\frac{\frac{g_1}{r_1^2}}{r_2^2}=\frac{g_1}{r_1^2\times r_2^2}
We know that \(g_1\) is 9.8, but we don't know the value for \(r_1\) and \(r_2\). We will assume that \(r_1\) is equal to one. This means that \(r_2\) is equal to 4 :

image.png
You can now enter the values to obtain this final form :
g2=9.8(1)2×(4)2=9.8(4)2 g_2=\frac{9.8}{(1)^2\times (4)^2}=\frac{9.8}{(4)^2}
It gives you the same answer than your notes ! If you have any other questions, do not hesitate !

Explication d’élève
8 août 2021
You just take the weight of Earth radius and transform it on g. After, you multiply it by 3. And you have the answer ;-)!