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Student Question

Secondary V • 5mo.

Hello would anyone be able to explain me this type of chemistry question. I always seem to get these types of questions wrong and I just don’t understand why I’m not getting them.



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Explanations (1)

  • Explanation from Alloprof

    Explanation from Alloprof

    This Explanation was submitted by a member of the Alloprof team.

    Team Alloprof • 5mo.

    Hi SupraZinc,

    Thanks for your question!

    The ideal gas law is PV = nRT. Therefore, to determine P, you get P = (nRT)/V. Since R is constant, you can get rid of it for the exercice (since you don't need a true value of P, only a size comparison). Therefore, P = (nT)/V.

    The variables you wrote on the right of your picture are a great start! You can replace the variables in the ideal gas law with 1 if they remain unchanged and by 3 if they are trippled.

    So, initially, we have:

    P = (nT)/V = (1*1)/1 = 1

    After the changes:

    P = (3*3)/3 = 3

    So the pressure is tripled!

    You can always use this method for this kind of problem.

    Don't hesitate to reach out again if needed:)


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