Secondary V • 10mo.
Hello would anyone be able to explain me this type of chemistry question. I always seem to get these types of questions wrong and I just don’t understand why I’m not getting them.
Explanation from Alloprof
This Explanation was submitted by a member of the Alloprof team.
Hi SupraZinc,
Thanks for your question!
The ideal gas law is PV = nRT. Therefore, to determine P, you get P = (nRT)/V. Since R is constant, you can get rid of it for the exercice (since you don't need a true value of P, only a size comparison). Therefore, P = (nT)/V.
The variables you wrote on the right of your picture are a great start! You can replace the variables in the ideal gas law with 1 if they remain unchanged and by 3 if they are trippled.
So, initially, we have:
P = (nT)/V = (1*1)/1 = 1
After the changes:
P = (3*3)/3 = 3
So the pressure is tripled!
You can always use this method for this kind of problem.
Don't hesitate to reach out again if needed:)
Kylan