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Student Question

Secondary II • 3mo.

Hi can someone help with this math question please

IMG_2510.jpg


Mathematics
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Explanations (1)

  • Explanation from Alloprof

    Explanation from Alloprof

    This Explanation was submitted by a member of the Alloprof team.

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    Team Alloprof • 3mo.

    Hi 😊

    You have to use inequalities to solve.

    First, set your variables.

    x : number of lamps that have an electrical defect

    y : number of lamps that have an optical defect

    z : number of lamps that have both defects

    Then, make your inqualities.

    200 - 180 = 20

    20 lamps have at least one defect.

    x < 16

    y < 12

    x + y + z = 20

    You have to resolve :

    If you substract one lamp of each variable (x and y), you add one to z.

    Try with :

    x = 15

    y = 12

    z = 1

    You have :

    x + y + z = 20

    15 + 12 + 1 = 28 20

    You have to continue.

    x = 10

    y = 8

    z = 6

    x + y + z = 20

    10 + 8 + 6 = 24 20

    Again!

    x = 6

    y = 4

    z = 10

    x + y + z = 20

    6 + 4 + 10 = 20

    We did it! 😎

    So, we have :

    x = 6 lamps that have an electrical defect

    y = 4 lamps that have an optical defect

    z = 10 lamps that have both defects

    Hope this helped! 😁 Read you soon on the Help Zone 🥴

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