Skip to content

Zone d’entraide

Question de l’élève

Secondaire 5 • 28j

Bonsoir,

Est-ce que vous pouvez m’aider avec cette question? Merci beaucoup!!

image.png


Physique
avatar
avatar

{t c="richEditor.description.title"} {t c="richEditor.description.paragraphMenu"} {t c="richEditor.description.inlineMenu"} {t c="richEditor.description.embed"}

Explications (1)

  • Explication d'Alloprof

    Explication d'Alloprof

    Cette explication a été donnée par un membre de l'équipe d'Alloprof.

    Options
    Équipe Alloprof • 28j

    Thank you for your question!


    The simplest way to answer this question is to solve the equation that establishes that the addition of vectors A and B equals (16,0). The simplest way to do this is to decompose both vectors into their components, and thus, develop two equations:

    $$ \overline{A}cos(\theta) + \overline{B}cos(\theta) = 16 $$

    $$ \overline{A}sin(\theta) + \overline{B}sin(\theta) = 0 $$


    Simplifying both equations yields the following:

    $$ cos(\theta)(\overline{A}+\overline{B}) = 16 $$

    $$ sin(\theta)(\overline{A}+\overline{B}) = 0 $$


    One can then input the dimensions of both vectors and solve for theta:

    $$ cos(\theta)(10+10) = 16 $$

    $$ cos(\theta) = 16/20 = 0.8 $$

    $$ \theta = arccos(0.8) $$

    $$ \theta ≈ 36.9° $$


    There you go!


    This Alloprof webpage explains vector components:


    Don't hesitate to ask for more help!

Poser une question