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Secondary V • 4mo.

Bonsoir, comment on isole le x dans l'équation de la quadratique suivante:

(x-4)puissance2=28,8(y+5)

Mathematics
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Explanations (1)

  • Explanation from Alloprof

    Explanation from Alloprof

    This Explanation was submitted by a member of the Alloprof team.

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    Team Alloprof • 4mo. edited May 31

    Salut!


    Tu dois commencer par éliminer l'exposant 2 en effectuant l'opération inverse, soit une racine carrée :

    $$(x-4)^2=28,8(y+5)$$

    $$\sqrt{(x-4)^2}=\sqrt{28,8(y+5)}$$

    $$x-4=\sqrt{28,8(y+5)}$$


    Puis, il ne reste plus qu'à déplacer la constante 4 de l'autre côté :

    $$x=\sqrt{28,8(y+5)}+4$$


    Voilà! :)

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