Skip to content

Help Zone

Student Question

Secondary III • 6mo.

Could I have some help with this one?

IMG_20250607_144731.jpg


Mathematics
avatar
avatar

{t c="richEditor.description.title"} {t c="richEditor.description.paragraphMenu"} {t c="richEditor.description.inlineMenu"} {t c="richEditor.description.embed"}

Explanations (1)

  • Explanation from Alloprof

    Explanation from Alloprof

    This Explanation was submitted by a member of the Alloprof team.

    Options
    Team Alloprof • 6mo.

    Hi!


    You have:

    $$4a^2-9$$


    You can use the difference of squares technique to find the factors of this expression:

    $$(2a)^2-3^2$$

    $$(2a-3)(2a+3)


    So the factors are (2a-3) and (2a+3). The sum of these factors is:

    $$(2a-3)+(2a+3)$$

    $$2a-3+2a+3$$


    I'll let you do the maths ;)


    Reach out if there is anything else! 😁

Ask a question