Properties of Logarithmic Functions

Concept sheet | Mathematics
Table of contents

In the following animation, experiment with the values of parameters |a,| |b,| |c,| |h,| and |k| in the logarithmic function and observe their effects on the function’s properties. Then, read the concept sheet to learn more about each of the properties of the function.

Properties

Basic logarithmic function ||f(x)=\log_c x|| where |c>0| and |c \neq 1|

Log function in standard form ||f(x)=a\log_c \big(b(x-h)\big)+k|| where |c>0|, |c \neq 1,| and |a| and |b| are non-zero

Domain

The domain is |(0,\infty).|

If |b>0|, the domain is |(h,\infty).|

If |b<0|, the domain is |(-\infty,h).|

Range

​The range is |\mathbb{R}.|

The range is |\mathbb{R}.|

|x|-Intercept

​It is |x=1.|

It is the value of |x| such that |f(x)=0.|

|y|-Intercept of function

No |y|-intercept

If it exists, it is the value of |f(0).|

Sign

If |0<c<1|, the function is positive on |(0,1]| and negative on the rest of its domain.

If |c>1|, the function is negative on |(0,1]| and positive on the rest of its domain.

According to the equation of the function.

Increasing

​If |c>1.|

If |c>1| and |a| and |b| have the same sign.

If |0<c<1| and |a| and |b| have opposite signs.

Decreasing

If ​|0<c<1.|

If |c>1| and |a| and |b| have opposite signs.
If |0<c<1| and |a| and |b| have the same sign.

Asymptote

​|x=0|

|x=h|​

Extrema

None or depending on the context​.

None or depending on the context.

Example

Determine the properties of the logarithmic function. ||f(x)=-\log_{1/2}(2(x+1))+3||

It can be useful to plot a graph.

Graph of an increasing logarithm function
  • The equation of the asymptote of the function is |x=-1.|

  • The domain of the function is |(-1, + \infty).|

  • The range of the function is |\mathbb{R}.|

  • To calculate the |x|-intercept of the function, replace |f(x)| with |0| and isolate |x.| ||\begin{align} 0 &= - \log_{1/2} (2(x+1)) +3\\-3 &= - \log_{1/2} (2(x+1))\\3 &= \log_{1/2} (2(x+1))\end{align}|| Next, use exponent laws to rewrite the function. ||\begin{align} \displaystyle \left( \frac{1}{2} \right)^3 &= 2(x+1)\\ \displaystyle \frac{1}{8} &= 2(x+1)\\ \displaystyle \frac{1}{16} &= x+1\\ \displaystyle \frac{1}{16}-1&=x\\ \displaystyle -\frac{15}{16}&=x \end{align}||

  • To calculate the |y|-intercept, replace |x| with |0.| ||\begin{align}f(0) &= - \log_{1/2} (2(0+1)) +3\\ f(0) &= - \log_{1/2} (2) + 3\\ f(0) &= -1(-1) + 3\\ f(0) &= 4\end{align}||

  • Sign: the function is negative on |(-1, -\frac{15}{16}]| and positive on |[-\frac{15}{16},+\infty).|

  • Variation: the function is increasing over its entire domain.

  • The function has no extrema.