How do I calculate the intercepts of the following? , x + 2y-6=0, 2x-y=0, y= 1/2 x +4 .....
pls help asap
Explanation (1)
Student Explanation
September 11, 2025
Thank you for your question!
The intercept is a constant that is always added (or subtracted) to a linear equation.
In this case, all the examples you gave seem to follow the following form...
$$ y = ax + b $$
...where b is the intercept.
Your goal should thus be to express these equations under their canonical form and identify what the constant is.
Let's use the first equation you mentioned as example:
$$ x+2y-6=0 $$
Let's separate x and y on different sides of the equation:
$$ x+2y-2y-6=0-2y $$
$$ x-6 = -2y $$
We want the equation to be a function of y, so let's divide both sides by -2:
$$ \frac{x-6}{-2} = \frac{-2y}{-2} $$
$$ \frac{-x}{2}+3 = y $$
Let's slightly rearrange the equation to make it more clearly recognizable:
$$ y = -\frac{x}{2}+3 $$
Can you identify the constant in this equation?
This webpage from the Alloprof website explains the forms of the equation of a line:
Don't hesitate if you need more help!
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